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                         文中提及函数并非Oracle及SQL Server 的全部功能,尤其分析挖掘函数,并未完全涵盖,请以实际解决问题优先,勿妄谈二者优劣。 
  1.绝对值    S:select abs(-1) value    O:select abs(-1) value from dual 
    2.取整(大)    S:select ceiling(-1.001) value    O:select ceil(-1.001) value from dual 
    3.取整(小)    S:select floor(-1.001) value    O:select floor(-1.001) value from dual 
    4.取整(截取)    S:select cast(-1.002 as int) value    O:select trunc(-1.002) value from dual 
    5.四舍五入    S:select round(1.23456,4) value 1.23460    O:select round(1.23456,4) value from dual 1.2346 
    6.e为底的幂    S:select Exp(1) value 2.7182818284590451    O:select Exp(1) value from dual 2.71828182 
    7.取e为底的对数    S:select log(2.7182818284590451) value 1    O:select ln(2.7182818284590451) value from dual; 1 
    8.取10为底对数    S:select log10(10) value 1    O:select log(10,10) value from dual; 1 
    9.取平方    S:select SQUARE(4) value 16    O:select power(4,2) value from dual 16 
    10.取平方根    S:select SQRT(4) value 2    O:select SQRT(4) value from dual 2 
    11.求任意数为底的幂    S:select power(3,4) value 81    O:select power(3,4) value from dual 81 
    12.取随机数    S:select rand() value    O:select sys.dbms_random.value(0,1) value from dual; 
    13.取符号    S:select sign(-8) value -1    O:select sign(-8) value from dual -1 
  ----------数学函数 
    14.圆周率    S:SELECT PI() value 3.1415926535897931    O:不知道 
    15.sin,cos,tan 参数都以弧度为单位    例如:select sin(PI()/2) value 得到1(SQLServer) 
    16.Asin,Acos,Atan,Atan2 返回弧度 
    17.弧度角度互换(SQLServer,Oracle不知道)    DEGREES:弧度-〉角度    RADIANS:角度-〉弧度 
    ---------数值间比较 
    18. 求集合最大值    S:select max(value) value from    (select 1 value    union    select -2 value    union    select 4 value    union    select 3 value)a 
    O:select greatest(1,-2,4,3) value from dual 
    19. 求集合最小值    S:select min(value) value from    (select 1 value    union    select -2 value    union    select 4 value    union    select 3 value)a 
    O:select least(1,3) value from dual 
    20.如何处理null值(F2中的null以10代替)    S:select F1,IsNull(F2,10) value from Tbl    O:select F1,nvl(F2,10) value from Tbl 
    --------数值间比较 
    21.求字符序号    S:select ascii('a') value    O:select ascii('a') value from dual 
    22.从序号求字符    S:select char(97) value    O:select chr(97) value from dual 
    23.连接    S:select '11'+'22'+'33' value    O:select CONCAT('11','22')||33 value from dual 
  23.子串位置 --返回3    S:select CHARINDEX('s','sdsq',2) value    O:select INSTR('sdsq','s',2) value from dual 
    23.模糊子串的位置 --返回2,参数去掉中间%则返回7    S:select patindex('%d%q%','sdsfasdqe') value    O:oracle没发现,但是instr可以通过第四个参数控制出现次数    select INSTR('sdsfasdqe','sd',1,2) value from dual 返回6 
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