sql – 如何计算一对多关系
发布时间:2020-12-31 13:36:13  所属栏目:MsSql教程  来源:网络整理 
            导读:ReporterTbl与AttachmentTbl有一对多的关系. 在ReporterTbl中,我有一个ID(101),我可以使用AttachmentTbl多个与ReporterTbl.Id相关的附件 SELECT ISNULL(ReporterTbl.Id,0) AS Id,CONVERT(char(10),ReporterTbl.StartDate,101) AS StartDate,ISNULL(ReporterTb
                
                
                
            | 
                         ReporterTbl与AttachmentTbl有一对多的关系. 在ReporterTbl中,我有一个ID(101),我可以使用AttachmentTbl多个与ReporterTbl.Id相关的附件 SELECT ISNULL(ReporterTbl.Id,0) AS Id,CONVERT(char(10),ReporterTbl.StartDate,101) AS StartDate,ISNULL(ReporterTbl.PriorityId,0) AS PriorityId,ISNULL(dbo.ReporterTbl.PriorityDesc,'') AS PriorityDesc,(select ReporterTbl.Id,COUNT(dbo.AttachmentTbl.Id) AS attachment_Id FROM dbo.AttachmentTbl RIGHT OUTER JOIN ReporterTbl ON dbo.AttachmentTbl.Id = ReporterTbl.Id GROUP BY ReporterTbl.Id) AS IsAttachment ) 基本上,我想知道的是ReporterTbl.ID,我有多少个附件? 表结构: ReporterTbl
    Id int   {**PrimaryKey**}
    StartDate datetime
    PriorityId int
    PriorityDesc varchar(500
    AttachmentTbl:
    AttachmentId indentity
    Id {**FK to ReproterTbl**}
    Filename
    Content
    ...
解决方法select r.id,count(a.id) as Count from ReporterTbl r left outer join AttachmentTbl a on r.id = a.id group by r.id (编辑:泰州站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!  | 
                  

